Mathematics - Algebra - Ask NCERT
Question-Mathematics - Algebra - Ask NCERT class 8 Algebraic Expressions and Identities with solution questions answer. All ncert questions Answers for class 8 subject Mathematics chapter Algebraic Expressions and Identities and topic Algebra
If p = 2 - a, then prove that a3 + 6ap + p3 - 8 = 0
Question 1. Asked on :18 November 2022:11:05:37 AM
If p = 2 - a, then prove that a3 + 6ap + p3 - 8 = 0
-Added by Master Mind See More Answers Mathematics » Algebra
Answer:
Master Mind
Given: p = 2 - a
Putting the value of p into p(x)
P(x) = a3 + 6ap + p3 - 8 = 0
= a3 + 6a(2 - a) + (2 - a)3 - 8 = 0
= a3 + 12a - 6a2 + 23 - 3x22xa + 3x2xa2 - a3 - 8 = 0
= a3 + 12a - 6a2 + 8 - 12a + 6a2 - a3 - 8 = 0
= 0
Hence proved
-Answered by Master Mind On 18 November 2022:11:06:58 AM
Solve the equation 6(7b - 4) = 60 for b.
Question 2. Asked on :18 November 2022:11:06:33 AM
Solve the equation 6(7b - 4) = 60 for b.
-Added by ATP Admin See More Answers Mathematics » Algebra
Answer:
ATP Admin
Given equation is 6(7b - 4) = 60 Step by Step explanation
7b - 4 = 606
7b - 4 = 10
7b = 10 + 4
7b = 14
b = 147 = 2 Answer
-Answered by ATP Admin On 09 July 2019:11:53:03 PM
On dividing Polynomials x3+2x2-5ax-7 and x3+ax2-12x+6 by (x+1) and (x-2) respectively gives remainder R1 and R2. if 2R1+ R2 = 6 then find the value of a.
Question 3. Asked on :18 November 2022:01:05:56 PM
On dividing Polynomials x3+2x2-5ax-7 and x3+ax2-12x+6 by (x+1) and (x-2) respectively gives remainder R1 and R2. if 2R1+ R2 = 6 then find the value of a.
-Added by Akki chauhan See More Answers Mathematics » Algebra
Answer:
Shalu Shukla
-Answered by Shalu Shukla On 01 March 2019:03:47:38 PM
Q1. Simplify;3a - 2b - ab - (a-b+ab)+ 3ab +b - a
Question 4. Asked on :18 November 2022:01:06:07 PM
Q1. Simplify;
3a - 2b - ab - (a-b+ab)+ 3ab +b - a
-Added by Master Purushottam See More Answers Mathematics » Algebra
Answer:
Nishant Verma
3a-2b-ab-a+b-ab+3ab+b-a
take same terms like this
3a-a-a -2b+b+b -ab-ab+3ab
3a-a-a=a
-2b+b+b=0
-ab-ab+3ab= -2ab+3ab=ab
=a+0+ab
=a+ab
=a(1+b)
3a-2b-ab-(a-b+ab)+3ab+b-a
3a-2b-ab-a+b-ab+3ab+b-a
take same terms like this
3a-a-a -2b+b+b -ab-ab+3ab
3a-a-a=a
-2b+b+b=0
-ab-ab+3ab= -2ab+3ab=ab
=a+0+ab
=a+ab
=a(1+b)
-Answered by Nishant Verma On 17 October 2019:02:39:08 PM
Answer:
Master Purushottam
3a-2b-ab-a+b-ab+3ab+b-a
take same terms like this
3a-a-a -2b+b+b -ab-ab+3ab
3a-a-a=a
-2b+b+b=0
-ab-ab+3ab= -2ab+3ab=ab
=a+0+ab
=a+ab
=a(1+b)
3a-2b-ab-(a-b+ab)+3ab+b-a
3a-2b-ab-a+b-ab+3ab+b-a
take same terms like this
3a-a-a -2b+b+b -ab-ab+3ab
3a-a-a=a
-2b+b+b=0
-ab-ab+3ab= -2ab+3ab=ab
=a+0+ab
=a+ab
=a(1+b)
-Answered by Master Purushottam On 22 August 2019:08:55:31 PM
Answer:
Himanshi Verma
3a-2b-ab-a+b-ab+3ab+b-a
take same terms like this
3a-a-a -2b+b+b -ab-ab+3ab
3a-a-a=a
-2b+b+b=0
-ab-ab+3ab= -2ab+3ab=ab
=a+0+ab
=a+ab
=a(1+b)
3a-2b-ab-(a-b+ab)+3ab+b-a
3a-2b-ab-a+b-ab+3ab+b-a
take same terms like this
3a-a-a -2b+b+b -ab-ab+3ab
3a-a-a=a
-2b+b+b=0
-ab-ab+3ab= -2ab+3ab=ab
=a+0+ab
=a+ab
=a(1+b)
-Answered by Himanshi Verma On 22 March 2019:05:17:37 PM
Mathematics - Algebra - Ask NCERT
Mathematics - Algebra - Ask NCERT
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