Hi!

# Science - Motion - Ask NCERT

Question-Science - Motion - Ask NCERT class 0 with solution questions answer. All ncert questions Answers for class 0 subject Science chapter and topic Motion

## Shyam walks from position A to position F along the path ABCDEF.What is the total distance covered by Shyam during this motion?What is the magnitude of his displacement ? Are the two equal? ( AB=1 Km,BC=2 Km,CD=1 Km,DE=2 Km,EF=2 Km,FE=5 Km)

Asked on :31 May 2020:09:47:08 AM

## Shyam walks from position A to position F along the path ABCDEF.What is the total distance covered by Shyam during this motion?What is the magnitude of his displacement ? Are the two equal? ( AB=1 Km,BC=2 Km,CD=1 Km,DE=2 Km,EF=2 Km,FE=5 Km)

-Added by Aman Senapati Physics » Motion

Aman Senapati

Solution: The total distance covered by Shyam

=AB+BC+CD+DE+EF

=(1+2+1+2+2)Km = 8 Km

The magnitude of displacement of Shyam

= AF = 5 Km

The magnitude of displacement is less than the distance covered by him.

-Answered by Aman Senapati On 31 May 2020:10:02:26 AM

## Give a short note on displacement?

Asked on :31 May 2020:09:30:54 AM

## Give a short note on displacement?

-Added by Aman Senapati Physics » Motion

Aman Senapati

1. Displacement during a given time is the shortest distance measured from initial position of the object.
2. Displacement is characterised by its magnitude as well as direction. Thus,displacement is a vector.
3. Displacement can be positive or negative or even zero.

-Answered by Aman Senapati On 31 May 2020:09:40:08 AM

## Give a short note on distance?

Asked on :31 May 2020:09:26:44 AM

## Give a short note on distance?

-Added by Aman Senapati Physics » Motion

Aman Senapati

1. Distance is the total path length covered by an object during a given time.
2. Distance has a magnitude only and no direction.Thus,distance is a scalar.
3. Distance is always taken positive.

-Answered by Aman Senapati On 31 May 2020:09:44:50 AM

## Define rest?

Asked on :31 May 2020:09:23:01 AM

## Define rest?

-Added by Aman Senapati Physics » Motion

Aman Senapati

Objects,which are stationary and do not change their positions with time are, said to be at rest.

-Answered by Aman Senapati On 31 May 2020:09:24:55 AM

## Define motion?

Asked on :31 May 2020:09:22:12 AM

## Define motion?

-Added by Aman Senapati Physics » Motion

Aman Senapati

An object is said to be in motion when its position changes with time.

-Answered by Aman Senapati On 31 May 2020:09:23:53 AM

## What is displacement?

Asked on :28 September 2019:07:49:50 AM

## What is displacement?

-Added by Himanshi Verma Science » Motion

priyanshu kumar
It is defined as the change in position of an object. It is a vector quantity and has a direction and magnitude. It is represented as an arrow that points from the starting position to the final position. For Example- If an object moves from A position to B, then the object’s position changes. This change in position of an object is known as Displacement.

-Answered by Priyanshu Kumar On 30 September 2019:11:30:17 AM

Akki chauhan
It is defined as the change in position of an object. It is a vector quantity and has a direction and magnitude. It is represented as an arrow that points from the starting position to the final position. For Example- If an object moves from A position to B, then the object’s position changes. This change in position of an object is known as Displacement.

-Answered by Akki Chauhan On 28 September 2019:09:19:25 AM

## Explain why the below statements about displacements are not true.Displacements cannot be zeroDisplacements cannot be zeroThe magnitude of displacements are always greater than the distance travelled.The magnitude of displacements are always greater than the distance travelled.

Asked on :15 January 2019:06:06:35 PM

## Explain why the below statements about displacements are not true.Displacements cannot be zeroDisplacements cannot be zeroThe magnitude of displacements are always greater than the distance travelled.The magnitude of displacements are always greater than the distance travelled.

-Added by Harshita Rathore Science » Motion

Master Purushottam

(a) Not true, because if the initial and final position of the object is the same displacement can become zero.

(b) Not true, because, displacement is the shortest measurable distance between the initial and final positions of an object. It cannot be greater than the magnitude of the distance travelled by an object, but it can be smaller than the magnitude of the distance travelled by an object or , it may be equal to the distance travelled by the object.

-Answered by Master Purushottam On 24 August 2019:12:11:30 AM

Himanshi Verma

(a) Not true, because if the initial and final position of the object is the same displacement can become zero.

(b) Not true, because, displacement is the shortest measurable distance between the initial and final positions of an object. It cannot be greater than the magnitude of the distance travelled by an object, but it can be smaller than the magnitude of the distance travelled by an object or , it may be equal to the distance travelled by the object.

-Answered by Himanshi Verma On 20 January 2019:05:21:27 PM

## A man walks around a square street of side 10 m in 40 sec. Calculate the displacement of the man at the end of 2 minutes 20 seconds.

Asked on :15 January 2019:06:04:35 PM

## A man walks around a square street of side 10 m in 40 sec. Calculate the displacement of the man at the end of 2 minutes 20 seconds.

-Added by Himanshi Verma Science » Motion

Master Purushottam

The man takes 40 sec to cover ( 4 * 10 ) 40 metres. This shows he covers one metre in one sec.

In 2 min 20 sec (140 sec) , he will cover a distance of  140 metres.

Thus he completes  14040 = 3.5 rounds in 2 min 20 sec.

Hence it is noticed that he will be at the opposite side from where he started.

Now considering two simple cases.

Case (i)

If the man started at a corner of the square street:

In this case, the man would be diagonally opposite to the place from where he started

Displacement = diagonal of square with side 10 metre.

=   102+102

=   100

=14.1m

Case (ii)

The man started from the middle of the road.

After the end time, he is in the opposite side of the road.

Hence, the displacement is 10 metre.

-Answered by Master Purushottam On 24 August 2019:12:11:55 AM

Himanshi Verma

The man takes 40 sec to cover ( 4 * 10 ) 40 metres. This shows he covers one metre in one sec.

In 2 min 20 sec (140 sec) , he will cover a distance of  140 metres.

Thus he completes  14040 = 3.5 rounds in 2 min 20 sec.

Hence it is noticed that he will be at the opposite side from where he started.

Now considering two simple cases.

Case (i)

If the man started at a corner of the square street:

In this case, the man would be diagonally opposite to the place from where he started

Displacement = diagonal of square with side 10 metre.

=   102+102

=   100

=14.1m

Case (ii)

The man started from the middle of the road.

After the end time, he is in the opposite side of the road.

Hence, the displacement is 10 metre.

-Answered by Himanshi Verma On 19 January 2019:04:25:08 PM

Akki chauhan

The man takes 40 sec to cover ( 4 * 10 ) 40 metres. This shows he covers one metre in one sec.

In 2 min 20 sec (140 sec) , he will cover a distance of  140 metres.

Thus he completes  14040 = 3.5 rounds in 2 min 20 sec.

Hence it is noticed that he will be at the opposite side from where he started.

Now considering two simple cases.

Case (i)

If the man started at a corner of the square street:

In this case, the man would be diagonally opposite to the place from where he started

Displacement = diagonal of square with side 10 metre.

=   102+102

=   100

=14.1m

Case (ii)

The man started from the middle of the road.

After the end time, he is in the opposite side of the road.

Hence, the displacement is 10 metre.

-Answered by Akki Chauhan On 19 January 2019:10:47:33 AM

Akki chauhan

=14.1m

After the end time, he is in the opposite side of the road.

Hence, the displacement is 10 metre.

-Answered by Akki Chauhan On 19 January 2019:10:46:48 AM

Himanshi Verma

The man takes 40 sec to cover ( 4 * 10 ) 40 metres. This shows he covers one metre in one sec.

In 2 min 20 sec (140 sec) , he will cover a distance of  140 metres.

Thus he completes  14040 = 3.5 rounds in 2 min 20 sec.

Hence it is noticed that he will be at the opposite side from where he started.

Now considering two simple cases.

Case (i)

If the man started at a corner of the square street:

In this case, the man would be diagonally opposite to the place from where he started

Displacement = diagonal of square with side 10 metre.

=   102+102

=   100

=14.1m

Case (ii)

The man started from the middle of the road.

After the end time, he is in the opposite side of the road.

Hence, the displacement is 10 metre.

-Answered by Himanshi Verma On 16 January 2019:05:14:13 PM

Akki chauhan

The man takes 40 sec to cover ( 4 * 10 ) 40 metres. This shows he covers one metre in one sec.

In 2 min 20 sec (140 sec) , he will cover a distance of  140 metres.

Thus he completes  14040 = 3.5 rounds in 2 min 20 sec.

Hence it is noticed that he will be at the opposite side from where he started.

Now considering two simple cases.

Case (i)

If the man started at a corner of the square street:

In this case, the man would be diagonally opposite to the place from where he started

Displacement = diagonal of square with side 10 metre.

=   102+102

=   100

=14.1m

Case (ii)

The man started from the middle of the road.

After the end time, he is in the opposite side of the road.

Hence, the displacement is 10 metre.

-Answered by Akki Chauhan On 16 January 2019:10:04:11 AM

Harshita Rathore

The man takes 40 sec to cover ( 4 * 10 ) 40 metres. This shows he covers one metre in one sec.

In 2 min 20 sec (140 sec) , he will cover a distance of  140 metres.

Thus he completes  14040 = 3.5 rounds in 2 min 20 sec.

Hence it is noticed that he will be at the opposite side from where he started.

Now considering two simple cases.

Case (i)

If the man started at a corner of the square street:

In this case, the man would be diagonally opposite to the place from where he started

Displacement = diagonal of square with side 10 metre.

=   102+102

=   100

=14.1m

Case (ii)

The man started from the middle of the road.

After the end time, he is in the opposite side of the road.

Hence, the displacement is 10 metre.

-Answered by Harshita Rathore On 15 January 2019:06:05:41 PM

## What is retardation?

Asked on :07 January 2019:12:54:06 AM

## What is retardation?

Nishant Verma

Negative acceleration is called retardation.

-Answered by Nishant Verma On 17 October 2019:02:39:46 PM

Akki chauhan

Negative acceleration is called retardation.

-Answered by Akki Chauhan On 10 January 2019:10:56:09 AM

Negative acceleration is called retardation.

Negative acceleration is called retardation.

## Ask the Question that you Have?

#### Do you have a question to ask?

Science - Motion - Ask NCERT

You can see here all the solutions of this question by various user for NCERT Solutions. We hope this try will help you in your study and performance.

This Solution may be usefull for your practice and CBSE Exams or All label exams of secondory examination. These solutions or answers are user based solution which may be or not may be by expert but you have to use this at your own understanding of your syllabus.

## Search your Question Or Keywords

#### Do you have a question to ask?

You can ask your question or home work easily from ncert books any subject any chapter to go on Ask Question page.

User Earned Point: Select

## All Tags by Subjects:

Science (2380)
History (333)
Geography (311)
Economics (262)
Political Science (100)
Mathematics (410)
General Knowledge (5812)
Biology (94)
Physical Education (20)
Chemistry (118)
Civics (113)
Sociology (9)
Hindi (47)
English (371)
Physics (1435)
Other (98)
Accountancy (378)