Question 1. Asked on :24 June 2021:06:10:31 PM
If the HCF of 210 and 55 is expressible in the form 210 × 5 + 55y then find y.
-Added by Master Mind Mathematics » Real Numbers
Answer:
210 = 55 × 3 + 45
55 = 45 × 1 + 10
45 = 10 × 4 + 5
10 = 5 × 2 + 0
∴ HCF = 5
Now 210 × 5 + 55y = 5
1050 + 55y = 5
55y = 5 - 1050
55y = - 1045
y = - 104555 = - 19
y = - 19
-Answered by Master Mind On 24 June 2021:06:15:15 PM
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