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Question 1. Asked on :12 January 2019:05:52:26 PM

#### prove that the cyclic parallelogram is rectangle.

-Added by khushi chauhan Mathematics » Circles

Prince Rawat

Let ABCD is a parallelogram inscribed in circle.

Since ABCD is a cyclic parallelogram, then

∠A + ∠C = 180 ....1

But ∠A = ∠C

So ∠A = ∠C = 90

Again

∠B + ∠D = 180 ....2

But ∠B = ∠D

So ∠B = ∠D = 90

Now each angle of parallelogram ABCD is 90.

Hense ABCD is a rectangl

-Answered by Prince Rawat On 13 January 2019:12:27:03 PM(205Average Rating Based on rating)

Akki chauhan

Let ABCD is a parallelogram inscribed in circle.

Since ABCD is a cyclic parallelogram, then

∠A + ∠C = 180 ....1

But ∠A = ∠C

So ∠A = ∠C = 90

Again

∠B + ∠D = 180 ....2

But ∠B = ∠D

So ∠B = ∠D = 90

Now each angle of parallelogram ABCD is 90.

Hense ABCD is a rectangle

-Answered by Akki chauhan On 14 January 2019:10:19:58 AM(346Average Rating Based on rating)

khushi chauhan

∠A + ∠C = 180 ....1

But ∠A = ∠C

So ∠A = ∠C = 90

Again

∠B + ∠D = 180 ....2

But ∠B = ∠D

So ∠B = ∠D = 90

Now each angle of parallelogram ABCD is 90.

Hense ABCD is a rectangle

-Answered by khushi chauhan On 14 January 2019:06:02:22 PM(434Average Rating Based on rating)

Akki chauhan

∠A + ∠C = 180 ....1

But ∠A = ∠C

So ∠A = ∠C = 90

Again

∠B + ∠D = 180 ....2

But ∠B = ∠D

So ∠B = ∠D = 90

Now each angle of parallelogram ABCD is 90.

Hense ABCD is a rectangle

-Answered by Akki chauhan On 15 January 2019:09:05:05 AM(483Average Rating Based on rating)

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