Asked/Added Questions From NCERT:

Question 1. Asked on :13 January 2019:01:13:28 PM

Find the median of11,12,2x+2,3x,21,23 where x is the mean of 5,10,3.

-Added by Akki chauhan Mathematics » Probability

Answer:

Himanshi Verma

We know,

if the number of observation (n) is even

then,

1. first of all find the value at the position

2. and find the value at the position

3. now find the average of two value to get the median .

e.g.,

Given, 11, 12, 14, 18, (x + 2), (x + 4) , 30, 32 , 35 , 41 are in ascending order .

number of terms = 10 {even}

so, median = {(n/2)th + (n/2 + 1) th }/2

24 = (5th + 6th)/2

24 = {(x + 2) + (x + 4)}/2

24 = (x + 3)

x = 21

hence, x = 21

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-Answered by Himanshi Verma On 20 January 2019:05:27:04 PM(928Average Rating Based on rating)

Answer:

Jyoti Srivastva

We know,

if the number of observation (n) is even

then,

1. first of all find the value at the position

2. and find the value at the position

3. now find the average of two value to get the median .

e.g.,

Given, 11, 12, 14, 18, (x + 2), (x + 4) , 30, 32 , 35 , 41 are in ascending order .

number of terms = 10 {even}

so, median = {(n/2)th + (n/2 + 1) th }/2

24 = (5th + 6th)/2

24 = {(x + 2) + (x + 4)}/2

24 = (x + 3)

x = 21

hence, x = 21

-Answered by Jyoti Srivastva On 30 January 2019:04:32:47 PM(1140Average Rating Based on rating)

Answer:

Master Purushottam

We know,

if the number of observation (n) is even

then,

1. first of all find the value at the position

2. and find the value at the position

3. now find the average of two value to get the median .

e.g.,

Given, 11, 12, 14, 18, (x + 2), (x + 4) , 30, 32 , 35 , 41 are in ascending order .

number of terms = 10 {even}

so, median = {(n/2)th + (n/2 + 1) th }/2

24 = (5th + 6th)/2

24 = {(x + 2) + (x + 4)}/2

24 = (x + 3)

x = 21

hence, x = 21

-Answered by Master Purushottam On 23 August 2019:11:36:15 PM(4732Average Rating Based on rating)

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