**Question 1.** **Asked on :**15 January 2019:09:20:19 AM

The surface area of the cuboid is 1372 sq. cm. If its dimensions are in the ratio of 4:2:1. Then find length.

*-Added by Prince Rawat*

**Answer by: Master Purushottam**

The surface area of the cuboid= 1372 sq. cm

Let the dimensions =4x, 2x, 1x

The total surface area of the cuboid = 2(lb+bh+hl)=1372

= 2(4x × 2x + 2x × 1x + 4x × 1x )=1372

=2(8x^{2}+2x^{2}+4x^{2}) =1372

=2(14x^{2})= 1372

=28x^{2}=1372

= x^{2}=1372/28

= 49

x=7m

the dimensions are 4x=4×7=28m

2x=2×7=14m

1x=1×7=7m

*-Answered by Master Purushottam* On 24 August 2019:12:01:38 AM

**Answer by: Himanshi Verma**

The surface area of the cuboid= 1372 sq. cm

Let the dimensions =4x, 2x, 1x

The total surface area of the cuboid = 2(lb+bh+hl)=1372

= 2(4x × 2x + 2x × 1x + 4x × 1x )=1372

=2(8x^{2}+2x^{2}+4x^{2}) =1372

=2(14x^{2})= 1372

=28x^{2}=1372

= x^{2}=1372/28

= 49

x=7m

the dimensions are 4x=4×7=28m

2x=2×7=14m

1x=1×7=7m

*-Answered by Himanshi Verma* On 19 January 2019:05:17:58 PM

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