**Question 1.** **Asked on :**20 January 2019:10:13:42 AM

cotΦ-1/sinΦ=1

*-Added by Rohit Rajput*

**Answer:**

Cscϕ/secϕ = (1+cotϕ)/(1+tanϕ)

LHS = (1+cotϕ)/(1+tanϕ)

where cotϕ=cosϕ/sinϕ and tanϕ = sinϕ/cosϕ

= (1+(cosϕ/sinϕ))/(1+(sinϕ/cosϕ))

= ((cosϕ+sinϕ)/sinϕ)/((cosϕ+sinϕ)/cosϕ)

= cosϕ/sinϕ

wkt cosϕ=1/secϕ

and sinϕ=1/cosecϕ

= cscϕ/secϕ

LHS = RHS

Hence Proved

*-Answered by Himanshi Verma* On 22 January 2019:05:15:48 PM

**Answer:**

Cscϕ/secϕ = (1+cotϕ)/(1+tanϕ)

LHS = (1+cotϕ)/(1+tanϕ)

where cotϕ=cosϕ/sinϕ and tanϕ = sinϕ/cosϕ

= (1+(cosϕ/sinϕ))/(1+(sinϕ/cosϕ))

= ((cosϕ+sinϕ)/sinϕ)/((cosϕ+sinϕ)/cosϕ)

= cosϕ/sinϕ

wkt cosϕ=1/secϕ

and sinϕ=1/cosecϕ

= cscϕ/secϕ

LHS = RHS

Hence Proved

*-Answered by Master Purushottam* On 24 August 2019:12:17:05 AM

You can see here all the solutions of this question by various user for **NCERT Solutions**. We hope this try will help you in your study and performance.

This Solution may be usefull for your practice and **CBSE Exams** or All label exams of **secondory examination**. These solutions or answers are user based solution which may be or not may be by expert but you have to use this at your own understanding of your **syllabus**.

Our Expert Team reply with answer soon.

Ask Your Question

* Now You can earn points on every asked question and Answer by you. This points make you a valuable user on this forum. This facility is only available for registered user and educators.

Next moment you answer is ready .... go ahead ...

User Earned Point: Select

Sponsers link