**Question 1.** **Asked on :**09 January 2019:09:54:18 AM

Prove that if the chords are equal then the subtend angle at the center are equal?

*-Added by Master Purushottam*

**Answer:**

Given : In a circle C(O,r) , ∠AOB = ∠COD

To Prove : Chord AB = Chord CD .

Proof : In △AOB and △COD

AO = CO [radii of same circle]

BO = DO [radii of same circle]

∠AOB = ∠COD [given]

⇒ △AOB ≅ △COD [by SAS congruence axiom]

⇒ Chord AB = Chord CD [c.p.c.t]

*-Answered by Akki chauhan* On 13 January 2019:01:04:33 PM

**Answer:**

Given : In a circle C(O,r) , ∠AOB = ∠COD

To Prove : Chord AB = Chord CD .

Proof : In △AOB and △COD

AO = CO [radii of same circle]

BO = DO [radii of same circle]

∠AOB = ∠COD [given]

⇒ △AOB ≅ △COD [by SAS congruence axiom]

⇒ Chord AB = Chord CD [c.p.c.t]

*-Answered by Master Purushottam* On 22 August 2019:08:59:15 PM

**Answer:**

Given : In a circle C(O,r) , ∠AOB = ∠COD

To Prove : Chord AB = Chord CD .

Proof : In △AOB and △COD

AO = CO [radii of same circle]

BO = DO [radii of same circle]

∠AOB = ∠COD [given]

⇒ △AOB ≅ △COD [by SAS congruence axiom]

⇒ Chord AB = Chord CD [c.p.c

*-Answered by Shivang Gupta* On 25 August 2019:03:17:32 PM

**Answer:**

Given : In a circle C(O,r) , ∠AOB = ∠COD

To Prove : Chord AB = Chord CD .

Proof : In △AOB and △COD

AO = CO [radii of same circle]

BO = DO [radii of same circle]

∠AOB = ∠COD [given]

⇒ △AOB ≅ △COD [by SAS congruence axiom]

⇒ Chord AB = Chord CD [c.p.c

*-Answered by Nishant Verma* On 13 October 2019:09:36:46 AM

**Answer:**

Given : In a circle C(O,r) , ∠AOB = ∠COD

To Prove : Chord AB = Chord CD .

Proof : In △AOB and △COD

AO = CO [radii of same circle]

BO = DO [radii of same circle]

∠AOB = ∠COD [given]

⇒ △AOB ≅ △COD [by SAS congruence axiom]

⇒ Chord AB = Chord CD [c.p.c

*-Answered by Rahul Kumar * On 13 October 2019:10:01:29 AM

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