Question 1. Asked on :09 February 2019:04:37:21 PM
In the following figure, D and E are two points on BC such that BD = DE = EC. Show that ar (ABD) = ar (ADE) = ar (AEC). Can you answer the question that you have left in the ’Introduction’ of this chapter, whether the field of Budhia has been actually divided into three parts of equal area?
-Added by Harshita Rathore Mathematics » Areas Of Pallelograms And Triangles
Answer:
Let us draw a line segment AM ⊥ BC.
We know that,
Area of a triangle = 1/2 x Base x Altitude
It is given that DE = BD = EC.
⊥ Area (ΔADE) = Area (ΔABD) = Area (ΔAEC)
It can be observed that Budhia has divided her field into 3 equal parts.
-Answered by Himanshi Verma On 09 February 2019:04:40:18 PM
You can see here all the solutions of this question by various user for NCERT Solutions. We hope this try will help you in your study and performance.
This Solution may be usefull for your practice and CBSE Exams or All label exams of secondory examination. These solutions or answers are user based solution which may be or not may be by expert but you have to use this at your own understanding of your syllabus.
Our Expert Team reply with answer soon.
Ask Your Question
* Now You can earn points on every asked question and Answer by you. This points make you a valuable user on this forum. This facility is only available for registered user and educators.
Next moment you answer is ready .... go ahead ...
User Earned Point: Select
Sponsers link