**Question 1.** **Asked on :**07 October 2019:11:34:52 AM

**How many zeros does the polynomial (x – 3)2 – 4 can have? Also, find its zeroes.**

*-Added by Himanshi Verma*

**Answer:**

Given equation is (x – 3)2 – 4

Now, expand this equation.

=> x2 + 9 – 6x – 4

= x2 – 6x + 5

As the equation has a degree of 2, the number of zeroes it will have is 2.

Now, solve x2 – 6x + 5 = 0 to get the roots.

So, x2 – x – 5x + 5 = 0

=> x(x-1) -5(x-1) = 0

=> (x-1)(x-5)

So, the roots are 1 and 5.

*-Answered by Himanshi Verma* On 07 October 2019:11:36:47 AM

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