**Question 1.** **Asked on :**16 October 2019:07:59:32 PM

Why magnification is taken negative for real images and positive for virtual images?

*-Added by Himanshi Verma*

**Answer:**

If image is real, it will be inverted which means height of image will be taken as negative. Also, the height of object is always positive.

Now as magnification = Height of image / Height of object.

Therefore, in case of real image,

Magnification = Height of image (-) / height of object (+)=Negative.

So, Magnification will be negative.

Similarly, if image is virtual, it will be erect.

Therefore, in case of virtual image,

Magnification = Height of image (+) / height of object (+)= Positive

So, Magnification will be positive.

*-Answered by Himanshi Verma* On 16 October 2019:08:00:38 PM

**Answer:**

If image is real, it will be inverted which means height of image will be taken as negative. Also, the height of object is always positive.

Now as magnification = Height of image / Height of object.

Therefore, in case of real image,

Magnification = Height of image (-) / height of object (+)=Negative.

So, Magnification will be negative.

Similarly, if image is virtual, it will be erect.

Therefore, in case of virtual image,

Magnification = Height of image (+) / height of object (+)= Positive

So, Magnification will be positive.

*-Answered by priyanshu kumar* On 17 October 2019:08:35:34 AM

**Answer:**

If image is real, it will be inverted which means height of image will be taken as negative. Also, the height of object is always positive.

Now as magnification = Height of image / Height

Therefore, in case of real image,

Magnification = Height of image (-) / height of object (+)=Negative.

So, Magnification will be negative.

Similarly, if image is virtual, it will be erect.

Therefore, in case of virtual image,

Magnification = Height of image (+) / height of object (+)= Positive

So, Magnification will be positive. of object.

*-Answered by Nishant Verma* On 17 October 2019:02:32:30 PM

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