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Question 1. Asked on :25 May 2020:08:00:22 AM

#### Q-1)Find the area of trapezium PQRS with height PQ where SP=12cm,SR=13cm,QR=7cm?

-Added by Aman Senapati Mathematics » Herons Formula

Aman Senapati

Given,

• PS=12m
• SR=13m
• QR=7m

PQRS is a trapezium.

let SUR is a triangle and PQUR is a rectangle.

then SU=PS-QR

SU=12m-7m

SU=5m.

By Pythagorous theorm:-

(H sq.)=(P sq.) + (B sq.)

(13m sq.)=(P sq.) + (5m sq.)

169 sq. m=(P sq.) + 25 sq.m

169-25=(P sq.)

144=(P sq.)

√144=P

√12*12=P

12m=P

UR = 12m

According to the property of rectangle ( Opposite side's are equal )

UR=PQ

∴ PQ=12m.

-Answered by Aman Senapati On 25 May 2020:08:46:56 AM(18245Average Rating Based on rating)

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