Asked/Added Questions From NCERT: Mathematics
Question 3. Asked on : 16 January 2019:06:13:49 PM
An integer that is divisible by 2 is called ?
Added by Shalu Shukla Mathematics » G.k
Answer:
Himanshi Verma
An integer that is divisible by 2 is called Even Number.
Answered by Himanshi Verma On 17 January 2019:05:28:03 PM
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Question 4. Asked on : 16 January 2019:06:14:35 PM
Counting number are kept under _______ number.
Added by Himanshi Verma Mathematics » G.k
Answer:
Harshita Rathore
Counting numbers are numbers you can use to count whole items. You can use the positive integers to count marbles, for example. Whether 0 is a counting number or not, that's a big debate you may or may not be interested in
Answered by Harshita Rathore On 17 January 2019:05:31:45 PM
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Question 7. Asked on : 16 January 2019:05:34:43 PM
How many digits are there in Hindu Arabic System?
Added by Himanshi Verma Mathematics » G.k
Answer:
Himanshi Verma
The HinduArabic numerals are the ten digits (0, 1, 2, 3, 4, 5, 6, 7, 8, 9). They are descended from Indian numerals, and the HinduArabic numeral system by which a sequence of digits such as "406" is read as a whole number was developed by Indian mathematicians.
Answered by Himanshi Verma On 17 January 2019:05:27:36 PM
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Question 8. Asked on : 15 January 2019:09:48:55 AM
The lateral surface area of a cube is 256cm^{2} . Find its volume.
Added by Prince Rawat Mathematics » SURFACE AREAS AND VOLUMES
Answer:
Himanshi Verma
Lateral Surface Area of cube=256 cm²
4(side)² =256 side²=256÷4 side²=64 side=√64=8 cm Volume of the cube=(side)³=8×8×8=512 cm³.
Answered by Himanshi Verma On 16 January 2019:06:04:58 PM
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Question 11. Asked on : 15 January 2019:09:24:30 AM
The total surface area of a cube is 150sq. cm. Find the perimeter of any one of its faces.
Added by Prince Rawat Mathematics » SURFACE AREAS AND VOLUMES
Answer:
Akki chauhan
Total surface area of cube is 150sq. cm
Total surface area of cube : 6a^{2}
^{To find perimeter of its one faces : ?}
Total surface area of cube =150sq.cm^{}
6a^{2 } =150sq.cm
= 150 6
= 25cm
=a^{2} = √25cm
=a = 5 cm
Perimeter of its one face is = 4 × a
= 4 × 5 cm
= 20 cm Answer
Answered by Akki chauhan On 16 January 2019:10:09:26 AM
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Question 23. Asked on : 13 January 2019:11:15:32 AM
Define concentric circles.
Added by Akki chauhan Mathematics » Circles
Answer:
Akki chauhan
The concentric circle are the circles with a common center the region between two concentric circle of different radii is called an annulus.
Answered by Akki chauhan On 15 January 2019:09:05:48 AM
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Question 24. Asked on : 12 January 2019:05:55:36 PM
add √125 + 2√27 and 5√5  √3
Added by khushi chauhan Mathematics » Number System
Answer:
Akki chauhan
√125 +2 √27 +(5 √5  √3)
=√5×5×5 +2√3×3×3 5√5 √3
=5√5 +6√3 5√5 √3
=5√3
Answered by Akki chauhan On 15 January 2019:09:05:29 AM
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Question 26. Asked on : 12 January 2019:05:52:26 PM
prove that the cyclic parallelogram is rectangle.
Added by khushi chauhan Mathematics » Circles
Answer:
Akki chauhan
∠A + ∠C = 180 ....1
But ∠A = ∠C
So ∠A = ∠C = 90
Again
∠B + ∠D = 180 ....2
But ∠B = ∠D
So ∠B = ∠D = 90
Now each angle of parallelogram ABCD is 90.
Hense ABCD is a rectangle
Answered by Akki chauhan On 15 January 2019:09:05:05 AM
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Question 27. Asked on : 12 January 2019:10:52:27 AM
Find the zero of 2x5.
Added by Akki chauhan Mathematics » Number System
Answer:
Akki chauhan
2x5=0
2x=5
x= 5/2
Answered by Akki chauhan On 15 January 2019:09:04:26 AM
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Question 28. Asked on : 12 January 2019:10:49:51 AM
Factorise:
x^{3} 23x^{2} +142x120
Added by Akki chauhan Mathematics » Polynomials
Answer:
Himanshi Verma
x ^{3 } 23x ^{2} +142x120
=x^{3} x^{2} 22x^{2} +22x+120120
=x^{2} (x1)22x(x1)+120(x1)
=(x1)(x^{2} 22x+120)
=(x1)(x^{2} 12x10x+120)
=(x1)[x(x12)10(x12)]
=(x1)(x10)(x12)
Answered by Himanshi Verma On 16 January 2019:05:57:48 PM
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Question 31. Asked on : 11 January 2019:02:55:18 PM
Find the median of first 10 prime numbers.
Added by Prince Rawat Mathematics » STATISTICS
Answer:
Akki chauhan
The first 10 prime numbers are : 2,3,5,7,11,13,17,19,23 and 29.
n=10
Median if n is even numbers
n 2 th term = 5th term = 11
n 2 + 1 = 5 + 1 = 6th term = 13
Median = 5th term + 6th term 2
Median = 11 + 13 2
= 24 2 = 12 Answer
Answered by Akki chauhan On 15 January 2019:09:03:48 AM
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Question 32. Asked on : 11 January 2019:10:18:43 AM
Define frequency of the observation.
Added by Prince Rawat Mathematics » STATISTICS
Answer:
Rohit Rajput
The number of times an observation occurs in the given data is called frequency of the observation.
Answered by Rohit Rajput On 12 January 2019:08:59:05 AM
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Question 34. Asked on : 11 January 2019:10:04:29 AM
What is Degree of the Polynomials?
Added by Prince Rawat Mathematics » POLYNOMIALS
Answer:
Prince Rawat
Highest power of x in the algebraic expression is called the degree of the polynomials.
Answered by Prince Rawat On 11 January 2019:10:08:00 AM
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Question 35. Asked on : 09 January 2019:09:54:18 AM
Prove that if the chords are equal then the subtend angle at the center are equal?
Added by Master Purushottam Mathematics » Circles
Answer:
Akki chauhan
Given : In a circle C(O,r) , ∠AOB = ∠COD
To Prove : Chord AB = Chord CD .
Proof : In △AOB and △COD
AO = CO [radii of same circle]
BO = DO [radii of same circle]
∠AOB = ∠COD [given]
⇒ △AOB ≅ △COD [by SAS congruence axiom]
⇒ Chord AB = Chord CD [c.p.c.t]
Answered by Akki chauhan On 13 January 2019:01:04:33 PM
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Question 36. Asked on : 09 January 2019:09:37:10 AM
Ques.1. prove that 2+2= 5
Added by Master Purushottam Mathematics » Number System
Answer:
Akki chauhan
Start with: 20 = 20
Which is the same as: 1636 = 2545 Which can also be expressed as: (2+2) 2 (9 X (2+2) = 52) 9 X 5 Add 81/4 to both sides: (2+2) 2 (9 X (2+2) + 81/4 = 52) 9 X 5 + 81/4 Rearrange the terms: ({2+2}) 9/2) 2 = (59/2) 2 Ergo: 2+2  9/2 = 5 Hence: 2 + 2 = 5
Answered by Akki chauhan On 15 January 2019:09:03:13 AM
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Question 37. Asked on : 09 January 2019:09:36:20 AM
Added by Master Purushottam Mathematics » Number System
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Question 38. Asked on : 07 January 2019:02:34:53 PM
Q. simplify combining like terms
(1) 21b  32 +7b  20b
Added by Master Purushottam Mathematics » Algebra Expression
Answer:
Akki chauhan
21b  32 + 7b  20b
=(21b+7b 20b)  32
=8b  32 Answer
Answered by Akki chauhan On 10 January 2019:10:54:03 AM
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Question 39. Asked on : 07 January 2019:02:26:38 PM
Find the sum : 3p^{2} q^{2}  4pq + 5,  10p^{2} q^{2} , 15 + 9pq + 7p^{2} q^{2}
Added by Master Purushottam Mathematics » Algebra Expreesion
Answer:
Akki chauhan
3p ^{2} q ^{2}  4pq + 5 + (10p ^{2} q ^{2} ) + 15 + 9pq + 7p ^{2} q ^{2}
= 3p^{2} q^{2} + 7p^{2} q^{2}  10p^{2} q^{2} + 9pq  4pq + 5 + 15
= 10p^{2} q^{2}  10p^{2} q^{2} + 5pq + 20
= 5pq + 20 Answer
Answered by Akki chauhan On 10 January 2019:10:54:27 AM
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Question 45. Asked on : 07 January 2019:12:03:07 PM
What is mean?
Added by ATP Admin Mathematics » Mean
Answer:
Rohit Rajput
Mean is an average of some data which is calculated by dividing ∑Sum of data by total numbers of data

Answered by Rohit Rajput On 11 January 2019:09:59:24 AM
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Question 46. Asked on : 31 December 2018:02:20:01 PM
factorise x^{2} + 2x + 1
Added by ATP Admin Mathematics » Factorisation
Answer:
Akki chauhan
x ^{2} + 2x + 1
= x^{2} + x + x + 1
= x(x + 1) + 1(x + 1)
= (x + 1) (x + 1)
Answered by Akki chauhan On 10 January 2019:10:57:10 AM
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Question 47. Asked on : 31 December 2018:09:20:26 AM
Find the median of 11, 12, 2x + 2, 3x, 21, 23 where x is the mean of 5, 10, 3.
Added by ATP Admin Mathematics » Mean Median
Answer:
Akki chauhan
For finding the value of x first we find mean of 5, 10, 3
sum of observation = 5 + 10 + 3 = 18
mean = 18 / 3 = 6
Therefore, x = 6
Now we have data for median 11, 12, 14, 18, 21, 23
n = 6 { n is an even number}
n/2 th trem = 14
and (n/2 + 1)th trem = 18
Median = (14 + 18)/2 = 32/ 2 = 16 Answer
Answered by Akki chauhan On 14 January 2019:10:14:53 AM
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Question 48. Asked on : 29 December 2018:01:00:20 AM
If the sum of first 7 terms of an AP is 49 and that of 17 terms is 289, find the sum of first n terms.
Added by ATP Admin Mathematics » Arithmetic Progressions
Answer:
Akki chauhan
S7 = 7/2(2a + 6d)
=> 49 = 7a + 21d
=> 7 = a + 3d  (i)
S17 = 17/2 (2a + 16d)
=> 289 = 17a + 136
=> 17 = a + 8d  (ii)
Substracting equation (i) from (ii)
we have ...
17  7 = a  a + 8d  3d
10 = 5d
d = 10/5
d = 2
Putting the value in Equation (i)
7 = a + 3d
7 = a + 3 x 2
a = 7  6
a = 1
Sum of first n terms = n/2 [2a + (n  1) d]
= n/2 [2x 1 + (n  1)2]
= n/2 [2 + 2n  2 ]
= n/2 (2n)
= nxn = n2
Answered by Akki chauhan On 14 January 2019:10:14:29 AM
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