Given,
- Area of trapezium ABCE = 475 sq.cm
- Height = 19 cm.
- one side is 4 cm greater than the other.
Area of trapezium = 1/2 ( sum of // sides ) * H
let the // sides of trapezium are x and x + 4.
475 sq.cm = 1/2 ( x + x + 4) * 19cm.
475/19 = 2x + 42
25 * 2 = 2x + 4
50 - 4 = 2x
46 cm = 2x
46/2 = x
23=x
x + 4 = 23 + 4 = 27.
∴ // sides of trapezium are 23 cm and 27 cm.
-Answered by Aman Senapati On 25 May 2020:10:02:27 AM