Asked/Added Questions From NCERT:


Question 1. Asked on :13 May 2019:10:29:43 AM

 7 और  9 के बीच 10 परिमेय संख्या लिखे ?


-Added by ravi varma Mathematics » Maths

Answer:

Himanshi Verma

 The rational numbers between 7 and 9 are 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 90. 

-Answered by Himanshi Verma On 14 May 2019:11:11:27 AM


Question 2. Asked on :08 May 2019:10:19:35 AM

x का मान  ज्ञात कीजिए  2x-1=14-x?

-Added by ravi varma Mathematics » Maths

Answer:

Himanshi Verma

 2x-1=14-x

2x+x-1=14

3x=14+1

3x=15

x=5

-Answered by Himanshi Verma On 14 May 2019:11:10:09 AM


Question 3. Asked on :08 May 2019:10:15:06 AM

4z+3=6+2z 

-Added by ravi varma Mathematics » Maths

Answer:

Himanshi Verma

 4z+3=6+2z

4z-2z+3=6

2z+3=6

2z=6-3

2z=3

z=3/2

-Answered by Himanshi Verma On 14 May 2019:11:14:46 AM


Question 4. Asked on :01 March 2019:03:26:35 PM

 How to prove Pythagorus theorem .

-Added by Akki chauhan Mathematics » Maths

Answer:

Himanshi Verma

 ABC is a right angle triangle at B and BD is a perpendicular from B on to AC, the diagonal.


Triangles ABC and BDC are similar, as:

     . angle DBC = 90 - angle C = angle A

     . angle ABC = angle BDC = 90


Ratios of corresponding sides are equal.

     AB / BD = BC / DC = AC / BC

    So we get  BC² = AC * DC     --- (1)


Triangle ABC amd ADB are similar, as:

    . angle DBA = 90 - (90 - C) = angle C

    . angle ABC = 90 = angle ADB


so ratios of corresponding sides are equal

         AB / AD = BC / BD = AC / AB 

       So we get  AB² = AD * AC  --- (2)


  Add (1) and (2) to get:

       AB² + BC² = AC * ( AD + DC) = AC * AC = AC²


So the theorem is proved.

-Answered by Himanshi Verma On 01 March 2019:03:38:26 PM


Question 5. Asked on :20 January 2019:10:13:42 AM

 cotΦ-1/sinΦ=1

-Added by Rohit Rajput Mathematics » Maths

Answer:

Himanshi Verma

 Cscϕ/secϕ = (1+cotϕ)/(1+tanϕ) 

LHS = (1+cotϕ)/(1+tanϕ) 

where cotϕ=cosϕ/sinϕ and tanϕ = sinϕ/cosϕ 

= (1+(cosϕ/sinϕ))/(1+(sinϕ/cosϕ)) 

= ((cosϕ+sinϕ)/sinϕ)/((cosϕ+sinϕ)/cosϕ) 

= cosϕ/sinϕ 


wkt cosϕ=1/secϕ 

and sinϕ=1/cosecϕ 

= cscϕ/secϕ 


LHS = RHS 

Hence Proved

-Answered by Himanshi Verma On 22 January 2019:05:15:48 PM


Question 6. Asked on :18 January 2019:05:21:24 PM

Write the formula of cylinder open from the top ? 


-Added by khushi chauhan Mathematics » Maths

Answer:

Himanshi Verma

 Total surface area= 2πr(r+h) -πr2

curved surface area = 2πrh+πr2

-Answered by Himanshi Verma On 03 February 2019:04:44:16 PM


 

You can see here all the solutions of this question by various user for NCERT Solutions. We hope this try will help you in your study and performance.

This Solution may be usefull for your practice and CBSE Exams or All label exams of secondory examination. These solutions or answers are user based solution which may be or not may be by expert but you have to use this at your own understanding of your syllabus.

 

 

Search your Question Or Keywords

 

 

Do you have a question for ask?

 

Ask Your Question

All Tags by Subjects: