Asked/Added Questions From NCERT:


Question 1. Asked on :31 March 2019:01:14:39 PM

 If the side of the square is increased by 50% the ratio of the area of the resulting square is the area of the resulting square to the area of the given square is:

-Added by Master Purushottam Mathematics » Mensuration

Answer:

Himanshi Verma

 Suppose, at first the side of the square was a

the area was a^2

now, the side of the square is (a+a★50/100)=a+a/2=3a/2

the area will be, 9a^2/4

so, 9a^2/4-a^2=5a^2/4

we now tell that, after increasing 50%of the side, the area will 5/4 times of the older(a^2).

-Answered by Himanshi Verma On 06 April 2019:06:44:55 PM


Question 2. Asked on :31 March 2019:01:06:03 PM

If the length of a rectangle is increased by 60% by what per cent would the width have to be decreased to maintain the same area?

-Added by Master Purushottam Mathematics » Mensuration

Answer:

Himanshi Verma




% Decrease

-Answered by Himanshi Verma On 06 April 2019:06:46:28 PM


Question 3. Asked on :31 March 2019:12:59:06 PM

 If the length and breadth of a rectangle plot are increased by 50% and 20% respectively, then the new area is how many times the original area

-Added by Master Purushottam Mathematics » Mensuration

Answer:

Hitesh kumar

  LET THE ORIGINAL LENGTH BE L

AND

ORIGINAL BREATH BE B.

ORIGINAL AREA = LB

LENGTH INCREASED BY 50% = 150 L / 100

BREATH INCREASED BY 20% = 120 B / 100

INCREASED AREA = 150 L X 120 B / 100 X 100

= 18000 LB / 10000

= 1.8 LB

NOW,

1.8 LB / LB = 1.8

CHANGING 1.8 INTO FRACTION.

1.8 = 18/10 = 9/5 

SO,

THE INCREASED AREA WILL BE 9/5 TIMES OF THE ORIGINAL AREA.

-Answered by Hitesh kumar On 13 April 2019:08:31:51 AM


Question 4. Asked on :31 March 2019:12:53:32 PM

The length of diagonal of the square whose area is 16900m2 is: 

-Added by Master Purushottam Mathematics » Mensuration

Answer:

Himanshi Verma

 so let us first consider a square with area x² unit²

so the side is of length √x² = x unit 

so square has angles of 90° so using Pythagoras we  get the length of the diagonal as  = 

√2x

so for this problem the area is 16900  m² so length of the side is √16900 = 130 m

so the length of the diagonal is √2 x 130 m = 130√2 m ≈ 183.82 m ANSWER

-Answered by Himanshi Verma On 06 April 2019:06:51:54 PM


Question 5. Asked on :31 March 2019:12:49:03 PM

 The perimeter of the rectangle field is 480m and the ratio between the length and breadth is 5 : 3. the area of the field  in square meters is :

-Added by Master Purushottam Mathematics » Mensuration

Answer:

Himanshi Verma

 The perimeter is given by twice the sum of length and breadth.

The length and  breadth are on ratio 5:3.Let the common ratio be x.
length = 5x
breadth = 3x
Perimeter = 2(length + breadth)
480 = 2(5x + 3x)
480 = 16x
x=30
length = 5x=5*30 = 150
breadth = 3x = 3*30 =90
Area = length * breadth
Area = 150 * 90
Area = 13500 sq. m 

-Answered by Himanshi Verma On 06 April 2019:06:53:50 PM


Question 6. Asked on :31 March 2019:12:34:26 PM

 A child walk 5m to cross a rectangular field  diagonally, if breadth of the field in 3m, its length is: 

-Added by Master Purushottam Mathematics » Mensuration

Answer:

Himanshi Verma



In the figure, ABCD is a rectangular field.
AC is the diagonal.
Triangle ABC, 
AC2=AB2+BC2
202=162+BC2
BC2=202162
=(20+16)(2016)=36×4
BC=6×2 = 12 m.
The breadth of the field is 12 m.

-Answered by Himanshi Verma On 06 April 2019:06:43:16 PM


 

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