Wellcome!

Himanshi Verma

Suppose, at first the side of the square was a

the area was a^2

now, the side of the square is (a+a★50/100)=a+a/2=3a/2

the area will be, 9a^2/4

so, 9a^2/4-a^2=5a^2/4

we now tell that, after increasing 50%of the side, the area will 5/4 times of the older(a^2).

-Answered by Himanshi Verma On 06 April 2019:06:44:55 PM

Question 2. Asked on :31 March 2019:01:06:03 PM

#### If the length of a rectangle is increased by 60% by what per cent would the width have to be decreased to maintain the same area?

-Added by Master Purushottam Mathematics » Mensuration

Himanshi Verma -Answered by Himanshi Verma On 06 April 2019:06:46:28 PM

Hitesh kumar

LET THE ORIGINAL LENGTH BE L

AND

ORIGINAL BREATH BE B.

ORIGINAL AREA = LB

LENGTH INCREASED BY 50% = 150 L / 100

BREATH INCREASED BY 20% = 120 B / 100

INCREASED AREA = 150 L X 120 B / 100 X 100

= 18000 LB / 10000

= 1.8 LB

NOW,

1.8 LB / LB = 1.8

CHANGING 1.8 INTO FRACTION.

1.8 = 18/10 = 9/5

SO,

THE INCREASED AREA WILL BE 9/5 TIMES OF THE ORIGINAL AREA.

-Answered by Hitesh kumar On 13 April 2019:08:31:51 AM

Question 4. Asked on :31 March 2019:12:53:32 PM

#### The length of diagonal of the square whose area is 16900m2 is:

-Added by Master Purushottam Mathematics » Mensuration

Himanshi Verma

so let us first consider a square with area x² unit²

so the side is of length √x² = x unit

so square has angles of 90° so using Pythagoras we  get the length of the diagonal as  =

√2x

so for this problem the area is 16900  m² so length of the side is √16900 = 130 m

so the length of the diagonal is √2 x 130 m = 130√2 m ≈ 183.82 m ANSWER

-Answered by Himanshi Verma On 06 April 2019:06:51:54 PM

Himanshi Verma

The perimeter is given by twice the sum of length and breadth.

The length and  breadth are on ratio 5:3.Let the common ratio be x.
length = 5x
480 = 2(5x + 3x)
480 = 16x
x=30
length = 5x=5*30 = 150
breadth = 3x = 3*30 =90
Area = 150 * 90
Area = 13500 sq. m

-Answered by Himanshi Verma On 06 April 2019:06:53:50 PM

Question 6. Asked on :31 March 2019:12:34:26 PM

#### A child walk 5m to cross a rectangular field  diagonally, if breadth of the field in 3m, its length is:

-Added by Master Purushottam Mathematics » Mensuration

Himanshi Verma In the figure, ABCD is a rectangular field.
AC is the diagonal.
Triangle ABC,
$A{C}^{2}=A{B}^{2}+B{C}^{2}$
${20}^{2}={16}^{2}+B{C}^{2}$
$B{C}^{2}={20}^{2}-{16}^{2}$
=$\left(20+16\right)\left(20-16\right)=36×4$
$BC=6×2$ = 12 m.
The breadth of the field is 12 m.

-Answered by Himanshi Verma On 06 April 2019:06:43:16 PM

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