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Question 1. Asked on :05 February 2019:05:11:52 PM

# The perimeter of a parallelogram is 60 cm and the ratio of its adjacent sides is 3:2 .If the altitude corresponding is 5 cm. Find the area of the parallelogram and the alyitude corresponding to the smaller side

-Added by Himanshi Verma Mathematics » Perimeter And Area

Himanshi Verma

Given

Ratio of side =3:2

Perimeter =60cm

Altitude =5cm

So let take one side as 3x and other is 2x

Then perimeter of parallelogram

=3x+2x+3x+2x

=10x

According to question perimeter =60cm

Then

10x=60cm

X=60/10=6cm

Then one side is =6 x 3=18

And other is =2x6=12

So base=18cm

Area of parallelogram =bxh

=18x5=90cm²

Altitude corresponding to smaller side

90=12xh

H=7.5cm

-Answered by Himanshi Verma On 05 February 2019:05:26:39 PM

Question 2. Asked on :28 January 2019:10:53:52 AM

#### A garden is 90 m long and 75 m broad. A path 5 m wide is  to be built outside and around it. find the area of the garden in hectare.

-Added by praful kumar Mathematics » Perimeter And Area

Himanshi Verma

Length (l) of garden = 90 m

Breadth (b) of garden = 75 m

Area of garden = l × b = 90 × 75 = 6750 m2

From the figure, it can be observed that the new length and breadth of the garden, when path is also included, are 100m and 85m respectively.

Area of the garden including the path = 100 × 85 = 8500 m2

Area of path = Area of the garden including the path − Area of garden

= 8500 − 6750 = 1750 m2

1 hectare = 10000 m2

Therefore, area of garden in hectare

=6750/10000

=0.675

-Answered by Himanshi Verma On 02 February 2019:01:49:33 PM

Question 3. Asked on :28 January 2019:10:49:14 AM

#### Find the area of a square park whose perimeter is 320m.

-Added by praful kumar Mathematics » Perimeter And Area

Himanshi Verma

A=6400m2

-Answered by Himanshi Verma On 03 February 2019:04:19:42 PM

Question 4. Asked on :17 January 2019:08:47:48 AM

#### path 1m wide built along the border and inside a square garden of side 30m. find ;                                                                                                   [i] The area of the path.[ii] the cost of planting grass in the remaining portion of the garden at the rate of Rs.40 per m2

-Added by Nitish kumar Mathematics » Perimeter And Area

Himanshi Verma

Let ABCD, the square garden of side= 30 m.

PQRS is the region inside the garden.

so,

PQ = (30 -1-1 ) = 28 m

also

PS = ( 30 – 1 – 1 ) = 28 m

(i) Area of the path = Area of ABCD – Area of PQRS

= [( 30 x 30) – (28 x 28)]

= 900 – 784

= 116 sq.m

(ii) Area of the remaining portion in which the grass is planted = Area of square PQRS

= 28 x 28

= 784 sq.m

cost of planting the grass in the region PQRS =  area x cost = 764 x 40

=31,360

-Answered by Himanshi Verma On 18 January 2019:05:16:10 PM

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